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For a photodiode, the forbidden energy g...

For a photodiode, the forbidden energy gap `(E_g)` of the material used is 2.8 eV and wavelength of radiations `(lambda)` incident on it is 5780 A. Then the emission of electrons is possible when incident radiation have.

A

`lambda`=5780 A

B

`lambdalt`5780 A

C

`lambdagt` 5780 A

D

none of these

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The correct Answer is:
B
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