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The number densities of electrons and holes in a pure germanium at room temperature are equal and its value is `2xx 10^(16)` per `m^(3)`. On doping with aluminium the hole density increases to `3.5 xx10^(22)` per `m^(3)`, then the electron density in doped germanium is

A

`1.1xx10^(10)m^(-3)`

B

`2.2xx10^(9)m^(-3)`

C

`3.3xx10^(9)m^(-3)`

D

`4.4 xx 10^(9)m^(-3)`

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The correct Answer is:
A
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