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A refrigerator with COP= 1//3 release 20...

A refrigerator with `COP= 1//3` release `200 J` at heat to a reservoir. Then the work done on the working substance is

A

`(100)/(3)J`

B

100J

C

`(200)/(3)J`

D

150J

Text Solution

Verified by Experts

The correct Answer is:
D
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