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A coil of inductor'L' is connected to an...

A coil of inductor'L' is connected to an a.c. source of emf E and frequency 'f'. The current in the coil is

A

`(E)/(sqrt2pifL)`

B

`(E)/(2pifL)`

C

`(E^2)/(2pifL)`

D

`(E)/(2pifL^2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the current in a coil of inductance \( L \) connected to an AC source of EMF \( E \) and frequency \( f \), we can follow these steps: ### Step 1: Understand the Concept of Inductive Reactance Inductive reactance (\( X_L \)) is the opposition that an inductor offers to the flow of alternating current (AC). It is given by the formula: \[ X_L = \omega L \] where \( \omega \) is the angular frequency. ### Step 2: Relate Angular Frequency to Frequency The angular frequency (\( \omega \)) is related to the frequency (\( f \)) by the equation: \[ \omega = 2\pi f \] ### Step 3: Substitute Angular Frequency into Inductive Reactance Substituting the expression for \( \omega \) into the formula for inductive reactance, we get: \[ X_L = 2\pi f L \] ### Step 4: Apply Ohm's Law According to Ohm's Law, the current (\( I \)) flowing through the circuit can be expressed as: \[ I = \frac{V}{R} \] In this case, the voltage \( V \) is the EMF \( E \), and the resistance \( R \) is the inductive reactance \( X_L \). Therefore, we can write: \[ I = \frac{E}{X_L} \] ### Step 5: Substitute Inductive Reactance into the Current Formula Now, substituting \( X_L \) into the equation for current, we have: \[ I = \frac{E}{2\pi f L} \] ### Conclusion Thus, the current in the coil is given by: \[ I = \frac{E}{2\pi f L} \] ### Final Answer The correct option for the current in the coil is: \[ \text{Option 2: } \frac{E}{2\pi f L} \]
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