A lens has a power of 10 D, when placed in air. When it is immersed in water `(mu =(4)/(3))` the change in power is (refractive index of lens material is 1.5)

A lens has a power of +5 D in air.If completely immersed in water,what will be its power ?Given,refractive index of glass = 3//2 ,refractive index of water = 4//3 .

The power of a lens kept in air is P. When it is immersed in water, then power becomes ( mu _(water) =4/3, mu_(Lens) = 3/2 )

The power of a lens kept in air is P. When it is immersed in water, then power becomes ( mu _(water) =4/3, mu_(Lens) = 3/2 )

A lens behaves as a converging lens in air and as a diverging lens in water. If refractive index of water is 1.33 , the refractive index of the material of the lens will be

A lens behaves as a converging lens in air and a diverging lens in water. The refractive index of the material is (refractive index of water =1.33 )

A lens behaves as a converging lens in air and a diverging lens in water. The refractive index of the material is (refractive index of water =1.33 )

A biconvex lens behaves as diverging lens in water and a converging lens in air. The refractive index of water is 1.33 and that of air is 1, the refractive index of the material of lens