`int (d theta)/(sin theta +sin 2theta)`

int (d theta)/((sin theta - 2 cos theta)(2 sin theta + cos theta))

int (d theta)/((sin theta - 2 cos theta)(2 sin theta + cos theta))

int (cos theta d theta)/(sin^(2) theta - 5 sin theta)

int(d theta)/((sin theta-2cos theta)(2sin theta+cos theta))=

Evaluate int_(0)^((pi)/(2))(cos theta d theta)/((sin theta +2)(sin theta +3)) .

int (cos theta d theta)/((1-sin theta)(2-sin theta))

int(d theta)/(sin theta cos^(3)theta) is equal to

int (1 + cos theta) / (theta + sin theta) d theta

Let the be an integrable function defined on [0,a] if I_(1)=int_(pi//2)^(pi//2) cos theta f(sin theta cos ^(2) theta)d theta and I_(2)=int_(0)^(pi//2)sin 2 theta f(sin theta cos ^(2) theta)d theta then