In a triangle ABC, having AD is median and area of triangle ABD= 120`m^2`. Find area of triangle ABC.

From the diagram,AD is median of triangle ABC and E is the midpoint of AD final area of triangle AEB (1)/(4) area of triangle ABC.What do you observe?

AD is a median of triangle ABC. G is a mid point of AD. If area of triangle ABC is 16 sq. cm. Find the area of triangle GDC

The centroid of a triangle ABC is G. The area of triangle ABC is 60 cm^(2) . The area of triangle GBC is.

In Delta ABC, AD is median. If area of Delta ABD = 25 cm^(2) find the area of Delta ABC .

The medians of a triangle ABC meet at G. If the area of the triangle be 120 sq cm, then the area of the triangle GBC is

Consider the following statements : 1. Let D be a point on the side BC of a triangle ABC: If area of triangle ABD = area of triangle ACD, then for all points O on AD, area of triangle ABO = area of triangle ACO. 2. If G is the point of concurrence of the medians of a triangle ABC, then area of triangle ABG = area of triangle BCO = area of triangle ACG. Which of the above statements is/are correct?

In the given figure AD is the median. If the area of Delta ABD = 10 cm^(2) , find the area of Delta ABC

In the given figure AD is the median. If the area of Delta ABD = 10 cm^(2) , find the area of Delta ABC

If triangle ABC ~ triangle DEF if DE : AB = 2 : 3 and area of triangle DEF = 44 sq.units then find the area of triangle ABC .

In triangle ABC, AD, BE and CF are the medians intersecting at point G and area of triangle ABC is 156 cm^(2) . What is the area (in cm^(2) ) of triangle FGE ?