If 500 ml of 1 M solution of glucose is mixed with 500ml of 1M solution of glucose final moalrity of solution will be:

100 ml of 0.1 M solution A is mixed with 20ml of 0.2 M solution B. The final molarity of the solution is :

1 ml of 1 M solution is mixed with 999 ml of pure water.

100 mL of 30% (m/v) NaOH solution is mixed with 100 mL of 90% (m/v) NaOH solution then the molarity of final solution will be-

500 ml of 2M NaCl solution was mixed with 200 ml of 2 M NaCl solution. Calculate the molarity of NaCl in final solution

500 ml of 2M NaCl solution was mixed with 200 ml of 2 M NaCl solution. Calculate the molarity of NaCl in final solution

1M of glucose solution has a freezing point of -1.86^(@)C . If 10 ml of 1M glucose is mixed with 30 ml of 3M glucose then the resultant solution will have a freezing point of

500 ml of 0.1 M AlCl_(3) is mixed with 500 ml of 0.1 M MgCl_(2) solution. Then calculation the molarity of Cl^(-) in final solution.

500 ml of 0.1 M AlCl_(3) is mixed with 500 ml of 0.1 M MgCl_(2) solution. Then calculation the molarity of Cl^(-) in final solution.