A black body is heated from `27^(@)C` to `127^(@)C`. The ratio of their energies of radiation emitted will be

A black body is heated from 7^(@)C to 287^(@)C . The ratio of radiation emitted is:

If a black body is heated from 27 ^@C to 927 ^@C , then the ratio of the radiation emitted by the body at the two temperatures will be

The temperature of a black body is increased from 7^(@)C to 567^(@)C , then the rate of energy radiation becomes

If the temperature of a black body incresese from 7^(@)C to 287^(@)C then the rate of energy radiation increases by

If temperature of a black body increases from 7^(@)C to 287^(@)C , then the rate of energy radiation increases by

If the temperature of a black body incresese from 7^(@)C to 287^(@)C then the rate of energy radiation increases by

The temperature of a body in increased from 27^(@)C to 127^(@)C . By what factor would the radiation emitted by it increase?

The temperature of a body in increased from 27^(@)C to 127^(@)C . By what factor would the radiation emitted by it increase?

The temperatures of two bodies A and B are 727^(@)C and 127^(@)C . The ratio of rate of emission of radiations will be

The temperatures of two bodies A and B are 727^(@)C and 127^(@)C . The ratio of rate of emission of radiations will be