In the given circuit, the diode has a forward resistance of 8 Ω and infinite backward resistance. The value of R is :-

The circuit shown in the fig. contains two diodes each with forward resistance of 50 Omega and infinite backward resistance. If the battery voltage is 6V, find the current through the 120 Omega resistance.

The circuit shown in the figure contains three diodes each with forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6 V, the current through the 100 ohm resistance is

The circuit shown in the figure contains two diodes each with a forward resistance of 50Omega and with infinite backward resistance. If the batter of 6 V is connected in the circuit, then the current through the 100 Omega resistance is

The circuit shown in the figure contains two diodes each with a forward resistance of 50 Omega and with infinite backward resistance. If the battery is 6 V, the current through the 100 Omega resistance (in ampere) is

The circuit shown in the figure contains two diodes each with a forward resistance of 30 Omega and with infinite backward resistance. If the battery is 3 V, the current through the 50 Omega resistance (in ampere) is

The circuit shown in the figure contains two diodes each with a forward resistance of 30 Omega and with infinite backward resistance. If the battery is 3 V, the current through the 50 Omega resistance (in ampere) is

The circuit shown in the figure contains two diodes each with a forward resistance of 30 Omega and with infinite backward resistance. If the battery is 3 V, the current through the 100 Omega resistance (in ampere)

In the given figure, each diode has a forward bias resistance of 30 Omega and infinite resistance in reverse bias. The current I_1 will be :