If a body is projected with a speed lesser than escape velocity, then

The escape velocity of a body from the earth is 11.2 km//s . If a body is projected with a velocity twice its escape velocity, then the velocity of the body at infinity is (in km//s )

If a body is projected with speed v greater than escape speed v_(e) from the surface of earth, find its speed in intersteller space.

If a body is projected with speed v greater than escape speed v_(e) from the surface of earth, find its speed in intersteller space.

Statement-1: If an object is projected from earth surface with escape velocity path of object will be parabola. Statement-2: When object is projected with velocity less than escape velocity from horizontal surface and greter than orbital velocity. path of object will be ellipse.

A body is projected with a velocity equal to twice the escape velocity (v_(e)) from the surface of the earth. With what velocity it will travel in interplanetary space?

Find the maximum height attained by a body projected with a speed v=v_(e)//2 . Where v_(e )= escape velocity of any object at earth's surface.