[(x)tan^(-1)(x-1)+tan^(-1)x+tan^(-1)(x+1)=tan],[(xi)sin^(-1)x+sin^(-1)2x=(pi)/(3)],[(xii)sin^(-1)x+sin^(-1)(1-x)=cos^(-1)x]

tan(sin^(-1)x+cos^(-1)x)

sin^(-1)((1-tan^(2)x)/(1+tan^(2)x))

tan (sin ^(-1)x+sin ^(-1) y) +tan (cos^(-1)x+cos ^(-1)y)

If Cos^(-1)x=Tan^(-1)x , then sin(Cos^(-1)x)=

If cos^(-1)x=tan^(-1)x , then sin(cos^(-1)x)=

If A = 1/pi [(sin^(-1)(xpi),tan^(-1)(x/pi)),(sin^(-1)(x/pi),cot^(-1)(pix))] B = 1/pi [(-cos^(-1)(xpi),tan^(-1)(x/pi)),(sin^(-1)(x/pi),-tan^(-1)(pix))] then A-B is equal to :

Range of sin^(-1)x+cos^(-1)x+tan^(-1)x is

f(x)=tan^(-1)x+tan^(-1)(1/x), g(x)=sin^(-1)x+cos^(-1)x are identical function if