When oxygen is passed through silent electric discharge, it is 10% converted to ozone
`3O_(2)(g) Leftrightarrow 2O_(3)(g)`
What volume of `O_(3)` will be formed by using30 litre of `O_(2)`?

Why silent electric discharge is used to convert O_(2) into O_(3) ?

On passing silent electric discharge through oxygen in an 5.5 mol % of oxygen is converted to ozone. How many moles of O_(2) and O_(3) moles of O_(2) is originally present?

90 mL of pure dry O_(2) is subjected to silent electric discharge. If only 10% of it is converted to O_(3) volume of the mixture of gases (O_(2)and O_(3)) after the reaction will be ------ and after passing through alkaline pyrogallol (absorbing agent of oxygen gas) will be

90 mL of pure dry O_(2) is subjected to silent electric discharge. If only 10% of it is converted to O_(3) volume of the mixture of gases (O_(2)and O_(3)) after the reaction will be ------ and after passing through alkaline pyrogallol (absorbing agent of oxygen gas) will be

100ml of dry oxygen is subjected to silent electric discharge ozone is formed.If 15% of O_(2) converted into O_(3) final mixture contains volume(s) of (under similar conditions of pressure and temperature)

100ml of dry oxygen is subjected to silent electric discharge ozone is formed.If 15% of O_(2) converted into O_(3) final mixture contains volume(s) of (under similar conditions of pressure and temperature)

Ammonia burns in oxygen as 2NH_(3)(g)+2.5O_(2)(g) to 2NO(g)+3H_(2)O(g) What volume of O_(2) at STP is required to produce 10 mol of products (4NO+6H_(2)O)?

2SO_2(g) +O_2(g) leftrightarrow 2SO_3(g) IF the volume of reaction vessel is increased, what happens to Kc. Explain.

An electric discharge is passed through a mixture containing 50cc of O_(2) and 50cc of H_(2) . The volume of the gases formed at 110^(@)C will be