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[" If "tan2(264)],[(a-2)+dots+(-1)^(n-1)...

[" If "tan2(264)],[(a-2)+dots+(-1)^(n-1)C_(n)(a-n)=a," where "C_(r)=^(n)C_(r)]

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If n>2, then prove that C_(1)(a-1)-C_(2)xx(a-2)+...+(-1)^(n-1)C_(n)(a-n)=a, where C_(r)=^(n)C_(r)

""^(n) C_(r+1)+2""^(n)C_(r) +""^(n)C_(r-1)=

""^(n) C_(r+1)+2""^(n)C_(r) +""^(n)C_(r-1)=

Find the sum 1xx2xx C_(1)+2xx3C_(2)+..+n(n+1)C_(n), where C_(r)=^(n)C_(r)

""^(n)C_(r+1)+^(n)C_(r-1)+2.""^(n)C_(r)=

""^(n)C_(r+1)+^(n)C_(r-1)+2.""^(n)C_(r)=

Show that .^(n)C_(r)+.^(n-1)C_(r-1)+.^(n-1)C_(r-2)=.^(n+1)C_(r) .

Prove that (C_(1))/(2)+(C_(3))/(4) +(C_(5))/(6)+….=2^(n)/(n+1) where C_(r) =^(n)C_(r)