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" 1."lim(x rarr pi/6)(sin(x-pi/6))/(sqrt...

" 1."lim_(x rarr pi/6)(sin(x-pi/6))/(sqrt(3)/2-cos x)

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Evaluate the following limits : Lim_( x to pi//6) (sin (x - pi/6))/(sqrt(3)/2 - cos x )

lim_( x to pi//6) (sin(x-pi//6))/(sqrt3//2-cosx) is equal to

lim_(x rarr pi)(sin(pi-x))/(pi(pi-x))

lim_(x rarr pi/3) (sin (pi/3-x))/(2 cos x-1) =

lim_ (x rarr pi) (sin3x) / (sin2x)

lim_(x rarr pi//3) (2 sin (x-pi//3))/(1-2 cos x) equals :

lim_(x rarr pi/2) [sin x] is :

lim_(x rarr pi/6) ((3sinx - sqrt3 cos x)/(6x-pi)) =