|[sqrt(6),2,3+sqrt(6)],[sqrt(12),sqrt(3)+sqrt(8)i,3sqrt(2)+sqrt(6)i],[sqrt(18),sqrt(2)+sqrt(12)i,sqrt(27)+2i]|=(6k)/(sqrt(2))" then "k=

The value of the determinant |{:(sqrt(6),2i,3+sqrt(6)i),(sqrt(12),sqrt(3)+sqrt(8)i,3sqrt(2)+sqrt(6)i),(sqrt(18),sqrt(2)+sqrt(12)i,sqrt(27)+2i):}| is (where i= sqrt(-1)

The value of the determinant |{:(sqrt(6),2i,3+sqrt(6)i),(sqrt(12),sqrt(3)+sqrt(8)i,3sqrt(2)+sqrt(6)i),(sqrt(18),sqrt(2)+sqrt(12)i,sqrt(27)+2i):}| is (where i= sqrt(-1)

The value of the determinant |{:(sqrt(6),2i,3+sqrt(6)i),(sqrt(12),sqrt(3)+sqrt(8)i,3sqrt(2)+sqrt(6)i),(sqrt(18),sqrt(2)+sqrt(12)i,sqrt(27)+2i):}| is (where i= sqrt(-1)

If Delta=|(sqrt(6),2i,3+sqrt(6)),(sqrt(12),sqrt(3)+sqrt(8)i,3sqrt(2)+sqrt(6)i),(sqrt(18),sqrt(2)+sqrt(12)i,sqrt(27)+2i)| then Delta is a)an integer b)a rational number c)an irrational number d)an imaginary number

(sqrt(2))/(sqrt(6)-sqrt(2))-(sqrt(3))/(sqrt(6)+sqrt(2))

((sqrt(3)+i sqrt(5))(sqrt(3)-i sqrt(5)))/((sqrt(3)+sqrt(2)i)-(sqrt(3)-i sqrt(2))

(2sqrt(6))/(sqrt(2)+sqrt(3))+(6sqrt(2))/(sqrt(6)+sqrt(3))-(8sqrt(3))/(sqrt(6)+sqrt(2))

(3sqrt(2))/(sqrt(3)+sqrt(6))-(4sqrt(3))/(sqrt(6)+sqrt(2))+(sqrt(6))/(sqrt(3)+sqrt(2))

([(sqrt(2)+i sqrt(3))+(sqrt(2)-i sqrt(3))])/([(sqrt(3)+1sqrt(2))+(sqrt(3)-1sqrt(2))])

If Delta=|(sqrt6,2i,3+sqrt6),(sqrt12,sqrt3+sqrt8i,3sqrt2+sqrt6i),(sqrt18,sqrt2+sqrt12i,sqrt27+2i)| then Delta is (i^2=-1)