The line `y=sqrt(2)x+4sqrt(2)` is normal to `y^2=4ax` then `a=`

The line y=sqrt(2)x+4sqrt(2) is normal to y^(2)=4ax then k=

The line y=sqrt(2)x+4sqrt(2) is normal to y^(2)=4ax is

The line y=x sqrt(2)+4 sqrt(2) is a normal to y^(2)=4 a x then a=

Prove that the chord y-sqrt(2)x+4asqrt(2)=0 is a normal chord of the parabola y^(2)=4ax . Also, find the point on the parabola where the given chord is normal to the parabola.

Find the equation of normal to the hyperbola x^(2)-y^(2)=16 at (4sec theta,4tan theta). Hence, show that the line x+sqrt(2)y=8sqrt(2) is a normal to this hyperbola.Find the coordinates of the foot of the normal.

Prove that the chord y-x sqrt(2)+4a sqrt(2)=0 is a normal chord of the parabola y^(2)=4ax . Also find the point on the parabola when the given chord is normal to the parabola.

The line sqrt(2y)-2x+8a=0 is a normal to the parabola y^(2)=4ax at P ,then P=

The line sqrt(2)y-2x+8a=0 is a normal to the parabola y^(2)=4ax at P .then P =

The chord of the parabola y^(2)=4ax, whose equation is y-x sqrt(2)+4a sqrt(2)=0, is a normal to the curve,and its length is sqrt(3)a then find lambda.

Statement 1: The line ax+by+c=0 is a normal to the parabola y^(2)=4ax. Then the equation of the tangent at the foot of this normal is y=((b)/(a))x+((a^(2))/(b)). Statement 2: The equation of normal at any point P(at^(2),2at) to the parabola y^(2)= 4ax is y=-tx+2at+at^(3)