If an avarage person jogs, he produces `14.5xx10^(4) cal//min`. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming `1 kg` requites `580xx10^(3)` cal for evaporation) is

If an average jogs, he produces 14.5xx10^(3) cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires 580xx10^(3) cal for evaporation) is

If an average jogs, he produces 14.5xx10^(3) cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires 580xx10^(3) cal for evaporation) is

If an average person jogs he produces 14.5 xx 10^3 cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires 580 xx 10^3 cal for evaporation) is

If an average person jogs, he produces 14.5 xx 10^3 cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires 580 xx 10^3 cal for evaporation ) is

If an average person jogs, he proiduces 14.5 xx 10^3 cal min^-1 . This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires 580 xx 10^3cal for evaporationa) is

If an average jogs, he produces 14.5xx10^(3) cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires 580xx10^(3) cal for evaporation) is a) 0.25 kg b) 2.25 kg c) 0.05 kg d) 0.20 kg

A metal rod AB of length 10x has its one end A in ice at 0^@C , and the other end B in water at 100^@C . If a point P one the rod is maintained at 400^@C , then it is found that equal amounts of water and ice evaporate and melt per unit time. The latent heat of evaporation of water is 540cal//g and latent heat of melting of ice is 80cal//g . If the point P is at a distance of lambdax from the ice end A, find the value lambda . [Neglect any heat loss to the surrounding.]