if `y=e^(3logx)` then`(dy)/(dx)`

If y=x^(logx) ,then (dy)/(dx)=

If y=x^((logx) then (dy)/(dx)=

If y=(logx)^3 then (dy)/(dx) =

If y=e^(1+logx)," then: "(dy)/(dx)

y=logx/(a+bx) then (dy)/(dx)

If y =(logx)^(x) then (dy)/(dx) =

If y = (e^x logx)/x^2 then (dy)/(dx)

If y = (e^x logx)/x^2 then (dy)/(dx)

If x^y=e^(x-y) , then (dy)/(dx) is (a) (1+x)/(1+logx) (b) (1-logx)/(1+logx) (c) not defined (d) (logx)/((1+logx)^2)

If y=e^(x^2+logx) , then dy/dx=?