If 18 g of glucose is present in 1000 g of solvent, the solution is said to be

If 180 g of glucose is present in 400 ml of solution, molarity of the solution is:

If 36.0 g of glucose is present in 400 ml of solution, molarity of the solution is:

If 36.0 g of glucose is present in 400 ml of solution, molarity of the solution is

If 18 gram of glucose (C_6H_(12)O_6) is present in 1000 gram of an aqueous solution of glucose it is said to be-

450 mg of glucose is dissolved in 100 g of solvent. What is the molality of the solution ?

The rise in the boiling point of a solution containing 1.8 g of glucose in 100 g of solvent is 0.1^(@)C . The molal elevation constant of the liquid is

Dissolving 180 g of glucose (mol.w.t. 180) in 1000g of water gave a solution of density 1.15 g/mL. The molarity of the solution is