`int_(-1)^(1) d/(dx) (tan^(-1)( 1/x))dx`

Options

A. 0
B. `- pi/4`
C. `-pi/2`
D. `pi/2`

Explanation

दिया है,
`overset(1)underset(-1)"lim" {(d)/(dx) (tan^(-1) 1/x)} dx`
`= [ tan^(-1) (1/x)]_(1)^(-1)`
`tan^(-1) - tan^(-1) (-1)`
` = (pi)/(4) + (pi)/(4) = (pi)/(2)`