Home
Class 12
PHYSICS
1" eV"=1.6xx10^(-19) J...

`1" eV"=1.6xx10^(-19)` J

Promotional Banner

Similar Questions

Explore conceptually related problems

when a beam of 10.6 eV photons of intensity 2.0 W//m^(2) falls on a platinum surface of area 1.0 xx 10^(4) m^(2) and work function 5.6 eV , 0.53 % of the incidentphotons eject photoelectrons find the number of photoelectrons emited per second and their minimum energies (in eV)Take 1 eV= 1.6 xx 10^(-19) J

Calculate the velocity of electron ejected from a platium surface when radiation of 200 nm falls on it .The work function of platinum is 5 eV(1 eV = 1.6 xx 10^(-19) J)

Calculate the velocity of electron ejected from a platium surface when radiation of 200 nm falls on it .The work function of platinum is 5 eV(1 eV = 1.6 xx 10^(-19) J)

Calculate the de-Broglie waveelngth of an electron of energy 400 eV.Given,lanck's constant = 6.6 xx 10^(-34) J s, mass of electron = 9.1 xx 10^(31) kg,1 eV = 1.6 xx 10^(-19) J .

The photoelectric threshold wavelength for Potassium having work function of 2eV is.......... (Take h= 6.6 xx 10^(-34) J s. 1 eV = 1.6 xx 10^(-19) J , C = 3 xx 10^8 Ms^(-1) )

Find the maximum velocity of photoelectrons emitted by radiation of frequency 3 xx 10^(15) Hz from a photoelectric surface having a work function of 4.0 eV. Given h=6.6 xx 10^(-34) Js and 1 eV = 1.6 xx 10^(-19) J.

Find the maximum velocity of photoelectrons emitted by radiation of frequency 3 xx 10^(15) Hz from a photoelectric surface having a work function of 4.0 eV. Given h=6.6 xx 10^(-34) Js and 1 eV = 1.6 xx 10^(-19) J.

The energy liberated in the combination of a hole-electron pair is converted into electromagnetic radiation.What is tha band gap,if the maximum wawveelngth fo th radiation emitted is 820 nm?Gien that 1 eV=1.6 xx 10^(-19) J and h=6.62 xx 10^(-34) Js .