`O^(2-)` is isoelectronic with

The formation of the oxide ion O^(2-)(g) , form oxygen atom requires first an exothermic and then an endothermic step as shown below, O(g)+e^(-) to O^(-)(g),DeltaH_(f)^(0)=-141kJ*mol^(-1) O^(-)(g)+e^(-) to O^(2-)(g),DeltaH_(f)^(0)=+780kJ*mol^(-1) ltbr. Thus, process of formations of O^(2-) in gas phase is unfavourable even through O^(2-) is isoelectronic with neon. it is due to the fact that-

The formation of the oxide ion O _((g)) ^(2-) from oxygen atom requires first an exothermic and then an endothermic step as shown below : O _((g)) + e ^(-) to O _((g )) ^(-) ,Delta _(f) H^(0) =-141 kJ mol ^(-1) O _((g)) ^(-) +e ^(-) to O _((g)) ^(-2) ,Delta _(f) H^(0) =+ 780 kJ mol ^(-1) Thus, process of formation of O^(2-) in gas phase is unfavourable even thrugh O ^(2-) is isoelectronic with neon. It is due to the fact that (2015)

The formation of oxide ion O^(2-)(g) from oxygen atom requires first an exothermic and then an endothermic step as shown below O(g)+e^(-) rarr O^(-)(g), DeltaH^(-) = - 141 kj mol^(-1) O^(-)(g) +e^(-) rarr O^(2-) (g), DeltaH^(-) =+ 780 kj mol^(-1) Thus, process of formation of O^(2-) in gas phase is unfavourable even through O^(2-) is isoelectronic with neon. It is due to the fact that

The formation of oxide ion O^(2-)(g) from oxygen atom requires first an exothermic and then an endothermic step as shown below O(g)+e^(-) rarr O^(-)(g), DeltaH^(-) = - 141 kj mol^(-1) O^(-)(g) +e^(-) rarr O^(2-) (g), DeltaH^(-) =+ 780 kj mol^(-1) Thus, process of formation of O^(2-) in gas phase is unfavourable even through O^(2-) is isoelectronic with neon. It is due to the fact that m

O_2^(2-) is isoelectronic with