" Equation "(1)/(r)=(1)/(8)+(3)/(8)cos theta" represents "

Equation (x-x_(1))/(cos theta)=(y-y_(1))/(sin theta)=r may represents- -

The radius of the circle with the polar equation r^(2) - 8r (sqrt(3) cos theta + sin theta) + 15 = 0 is

The polar equation cos theta + 7 sin theta= (1)/(r ) represents a

The value of (1)/(8) (3 - 4 cos 2 theta + cos 4 theta) is

Find the radius of the circle with the polar equation r^(2)-8r(sqrt(3)cos theta+sin theta+15=0

Let f( theta) = ( cos theta - "cos" (pi)/(8))(cos theta - "cos" (3 pi)/(8))(cos theta - "cos" (5 pi)/(8) )(cos theta - "cos" (7pi)/(8)) then :

Let f( theta) = ( cos theta - "cos" (pi)/(8))(cos theta - "cos" (3 pi)/(8))(cos theta - "cos" (5 pi)/(8) )(cos theta - "cos" (7pi)/(8)) then :

The value of (1+cos (pi)/(8))(1+cos (3 pi)/(8))(1+cos (5 pi)/(8))(1+cos (7 pi)/(8)) is

Express the following in a + ib form: (i) ((cos theta+ isin theta)/(sin theta + icos theta))^(4) (ii) ((cos 2theta -isin2theta)^(4)(cos4theta +isin4theta)^(-5))/((cos 3theta +isin3theta)^(-2) (cos 3theta -isin 3theta)^(-9)) (iii) ((sinpi//8 +icos pi//8)^(8))/((sinpi//8-icospi//8)^(8))