Divide `sqrt125 y^2` by `5y^2`

Divide (sqrt(125))y^(2) by 5y^(2)

Divide sqrt 125 :sqrt 5 .

Divide \sqrt{125} by \sqrt{5} .

Divide 10y^(2)z^(3) by 5y^(2)z

Divide 39y^3 (50y^2-98) by 26y^2 (5y+7) .

Divide: (2y^(2) - 3y^(3) + 5y-4) // (y-1)

Divide y^4-2 by 2y-1

Do as directed: (i) Add : sqrt(125 + 2 sqrt(27) and - 5 sqrt(5) - sqrt(3) (ii) Add: sqrt(7) - sqrt(11) and sqrt(5) - sqrt(11) + sqrt(13) (iii) Multiply : 2 sqrt(2) by 5 sqrt(2) (iv) Multiply : (-3 + sqrt(5)) by 3 (v) Divide : 7 sqrt(5) by - 14 sqrt(125) Divide : 7 sqrt(5) by -14 sqrt(125) (vi) Divide : 2 sqrt(216) - 3 sqrt(27) by 3

Divide as directed. 20(y + 4)(y^2 + 5y +3) div 5(y + 4)

If 250sqrt2x^3 − 5sqrt5y^3 = (5sqrt2x − sqrt5y) xx (Ax^2 + Bxy + Cy^2) , then the value of (A + C − sqrt(10)B) is: यदि 250sqrt2x^3 − 5sqrt5y^3 = (5sqrt2x − sqrt5y) xx (Ax^2 + Bxy + Cy^2) है तो (A + C − sqrt(10)B) का मान हैः