`dy/dx+2ytanx=sinx` at y=0, when `x=pi/3`

If dy/dx+2ytanx=sinx and y=0 , when x=pi/3 , show that the maximum value of y is 1/3

If dy/dx+2ytanx=sinx and y=0 , when x=pi/3 , show that the maximum value of y is 1/8

For the differential equation, find a particular solution satisfying the given condition: (dy)/(dx)+2ytanx=sinx ; y=0 when x=pi/3

For each of the differential equations given in find a particular solution satisfying the given condition : (dy)/(dx)+2ytanx=sinx,y=0 when x=(pi)/(3)

Solve dy/dx+2ytanx=sinx , y=0 , x=pi/3

Solve the following initial value problem: (dy)/(dx)+2ytanx=sinx ; y=0\ w h e n\ x=\ pi/3 .

dy/dx + 2y tan x = sinx, give y = 0 when x= pi/3

For the differential equation, find a particular solution satisfying the given condition: (dy)/(dx) + 2y tanx = sinx, y = 0 when x = pi/2

(dy)/(dx) + 2 y tan x = sin x, y = 0 when x = (pi)/(3) .