The equation of the plane perpendicular to the line `(x-1)/1=(y-2)/(-1)=(z+1)/2` and passing through the point (2,3,1), is

Equation of the plane perpendicular to the line (x)/(1)=(y)/(2)=(z)/(3) and passing through the point (2,3,4) is

Equation of the plane perpendicular to the line (x)/(1)=(y)/(2)=(z)/(3) and passing through the point (2,3,4) is

Equation of the plane perpendicular to the line (x )/(1) = (y )/(2) = ( z )/(3) and passing through the point (2,3,4) is :

Equation of the plane perpendicular to the line x/1=y/2=z/3 and passing through the point (2,3,4) is :

Equation of the plane perpendicular to the line x/1=y/2=z/3 and passing through the point (2, 3, 4) is

Prove that the equation of a plane perpendicular to the line x-1=2-y=(z+1)/(2) and passing through (2,3,

cartesian equation of the line which is perpendicular to the lines (x)/(2)=(y)/(1)=(z)/(3) and (x-3)/(-1)=(y-2)/(3)=(z+5)/(5) and passes through the point (1,2,3)

Find the equation of the plane passing through the line (x-1)/2=(y+1)/1=(z-3)/4 and perpendicular to the plane x+2y-z=12 .