`I.F.` of `1+(xtany-secy)(dy)/(dx)=0`

Solve: (dy)/(dx)=secy

The I.F. of "cosec x"=(dy)/(dx)+(ysec^(2)x)/("cosec x")=0 is

I.F.for y in y(dx)/(dy)+x-ln y=0 is

The I.F. of y log y(dx)/(dy)+x-log y=0 is

Solve the differential equation: (i) (1+y^(2))+(x-e^( tan ^(-1)y))(dy)/(dx)=0 (ii) x(dy)/(dx)+cos^(2)y=tan y(dy)/(dx)

If secy=xsec(a+y)," then "(sec^(2)y)(dy)/(dx)=