A plane passes through (1,-2,1) and is perpendicualr to two planes` 2x-2y+z=0" and "x-y+2z=4,` then the distance of the plane from the point (1,2,2) is

A plane passes through (1, -2, 1) and is perpendicular to two planes 2x - 2y + z=0 and x - y + 2z =4, then the distance of the plane from the point (1,2,2) is

A plane passes through (1,-2,1) and is perpendicular to two planes 2x-2y+z=0 and x-y+2z=4 . The distance of the plane form the point (1,2,2) is

A plane passes through (1, -2, 1) and is perpendicular to two planes 2x-2y+z=0 and x-y+2z=4. The distance of the plane from the point (0, 2, 2) is

A plane passes through (1, - 2, 1) and is perpendicular to the planes 2x - 2y +z = 0 and x-y + 2z = 4. The distance of the plane from the point (1, 2, 2) is:

A plane passes through the point P (1, -2,1) and is perpendiculai to t\\'o planes 2x - 2y + z =0 and x - y + 2z = 4. Then the equation of the plane is

Equation of plane passing through (-1,-1,2) and perpendicular to two planes x-2y+z=4 and x+2y-2z+4=0 is