An air capacitor of capacity `C = 10 mu F` is connected to a constant voltage battery of `12 V`. Now the space between the plates is filled with a liquid of dielectirc constant `5`. The charge that flows now from battery to the capacitor is

A parallel plate capacitor of capacitance 10 muF is connected across a battery of emf 5 mV. Now, the space between the plates of the capacitors is filled with a deielectric material of dielectric constant K=5. Then, the charge that will flow through the battery till equilibrium is reached is

A parallel plate capacitor of capacitance 10 muF is connected across a battery of emf 5 mV. Now, the space between the plates of the capacitors is filled with a deielectric material of dielectric constant K=5. Then, the charge that will flow through the battery till equilibrium is reached is

Consider a disconnected. Plate capacitor of capacity 10 mu with air filled in the gap between the plates. Now one-half of the space between the plates is filled with a dielectric of dielectric constant 4 as shown in .The capacity of the capacitor changes to .

Consider a disconnected plate capacitor of capacity 10 muF with air filled in the gap between the plates. Now one-half of the space between the plates is filled with a dielectric of dielectric constant 4 as shown in .The capacity of the capacitor changes to .

A cell of voltage V_0 is connected across a capacitor of capacitance C. Now the space between the plates is filled with a material of dielectric constant K. Find ratio of charge appear on the plates of capacitor before and after filling.

A parallel plate capacitor has a capacity 80xx10^(-6)F , when air is present between its plates. The space between the plates is filled with a dielectric slab of dielectric constant 20. The capacitor is now connected to a battery of 30V by wires. The dielectric slab is then removed. Then, the charge passing through the wire is

A capacitor of some capacitance is charged by a 12V battery.Now the space between the plates of capacitors is filled with a dielectric of dielectric constant K=0.5 and again it is charged. The magnitude of the charge will

A capacitor with air as the delectric is charged to a potential of 100 volts. If the space between the plates is now filled with a dielectric of dielectric constant 10 , the potential difference between the plates will be