" In the binomial expansion of "(a-b)^(n),n>5," the sum of "5" th and "6" th terms is zero,then "(a)/(b)" equals "

In the binomial expansion of (a-b)^(n) , n ge 5 , the sum of 5th and 6th terms is zero, then (a)/(b) equals

In the binomial expansion of (a-b)^n, n ge 5 , the sum of 5th and 6th terms is zero, then

In the binomial expansion of (a-b)^(n),nge5, the sum of 5th and 6th terms is zero then a/b equals:

In the binomial expansion of (a-b)^(n),nge5 , the sum of the 5th and 6th terms is zero. Then a/b equals:

In the binomial expansion of (a-b)^(n),n>=5 the sum of the 5 th and 6 th term is zero.Then a/b equals (n-5)/6 b.(n-4)/5 c.n/(n-4)d*6/(n-5)

In the binomial expansion of (a -b)^n, nge5 , the sum of the 5th and 6th terms is zero. Then a/b equals :

In the binomial expansion of (a - b)^n , n ge 5 the sum of the 5th and 6th term is zero , then find a/b