A particle is projected horizontally with a speed of `(40)/(sqrt3)m//s`, from some height `t = 0`. At what time its velocity makes `60^(@)` angle with initial velocity.
`(g=10m//s^(2))`

A particle is projected horizontally with speed (20)/(sqrt(3))m//s , from some height at t=0. At what time its velocity will make 60^(@) angle with initial velocity ?

A particle is projected horizontally with speed (20)/(sqrt(3))m//s , from some height at t=0. At what time its velocity will make 60^(@) angle with initial velocity ?

A body is projected horizontally with a velocity sqrt29 m/s from a height 10 m, the velocity on reaching the ground ………. m/s.

A particle is projected from ground with velocity 40sqrt(2)m//s at 45^(@) . At time t=2s

A particle is projected from ground with velocity 40sqrt(2)m//s at 45^(@) . At time t=2s

A particle is projected at an angle of 60^(@) above the horizontal with a speed of 10m//s . After some time the direction of its velocity makes an angle of 30^(@) above the horizontal. The speed of the particle at this instant is s

A particle is projected at an angle of 60^(@) above the horizontal with a speed of 10m//s . After some time the direction of its velocity makes an angle of 30^(@) above the horizontal. The speed of the particle at this instant is

Two particles are projected horizontally with same speed 30 m//s but in opposite directions from same height at time t = 0 . Calculate angle between velocity vectors of particles at time t = 3s .

A particle is projected from ground with velocity 40sqrt2m at 45^(@) .At time t=2s

A particle is projected horizontally with a speed V=5m/s from the top of a plane inclined at an angle theta=37^(@) to the horizontal (g=10m//s^(2)) What is the velocity of the particle just before it hits the plane?