The maximum velocity and maximum acceleration of a particle per for ming a linear SHM are `alpha and beta` respectively. Then path length of the particle is

The maximum velocity ad maximum acceleration of a particle performing a linear S.H.M. are alpha " and " beta respectively. Then the path length of the particle is

The maximum velocity and maximum acceleration of a particle in linear S.H.M. is 0.21m/s and 0.84 m/s^2 respectively . Find its period.

Maximum velocity and maximum acceleration of a particle executing SHM are beta" and "alpha respectively, what will its frquency?

If the maximum velocity and acceleration of a particle executing SHM are equal in magnitude the time period will be

The ratio of maximum velocity and maximum acceleration of a particle of SHM having amplitude A and angular frequency omega ………..

The maximum acceleration and the maximum velocity of a particle performing simple harmonic motion are a and B respectively.The amplitude will be?

If the maximum velocity and acceleration of a particle executing SHM are equal in magnitude, the time period will be

The maximum velocity and acceleration of a particle in S.H.M. are 100 cms/sec and 157 cm/ sec^2 respectively. The time period in seconds will be :

Where is maximum acceleration and zero acceleration of a particle executing SHM?