If the sum of the series `tan^(-1)3+tan^(-1)(9/2)+tan^(-1)(33/4)+......` to n terms = `((2n+1)pi)/(A)+B tan^(-1)(2^(n))` then `(A+B)` is equal to

Find the sum of the series tan^-1(1/2)+tan^-1(1/2)+tan^-1(1/18)+tan^-1(1/32)+............ to n terms

Find the sum of the series : (tan^(-1))(1)/(3)+(tan^(-1))(2)/(9)+...+(tan^(-1))(2^(n-1))/(1+2^(2n-1))+......oo

The sum of the series tan ^(-1)"" (1)/( 1 + 1 + 1 ^(2)) + tan ^(-1)"" (1)/( 1 + 2 + 2 ^(2)) + tan ^(-1) ""(1)/( 1 + 3 + 3 ^(2)) +... is equal to : a) pi/4 b) pi/2 c) pi/3 d) pi/6

The sum of the infinite terms of the series "tan"^(-1)((1)/(3))+ "tan"^(-1)((2)/(9)) + tan^(-1)((4)/(33)) + .... is equal to (pi)/(n) The value of n is:

The sum of the infinite terms of the series "tan"^(-1)((1)/(3))+ "tan"^(-1)((2)/(9)) + tan^(-1)((4)/(33)) + .... is equal to (pi)/(n) The value of n is:

Find the sum of the series : tan^- 1(1/3)+tan^- 1(2/9)+....+tan^- 1((2^(n-1))/(1+2^(2n-1)))+...... oo

Find the sum of the series : tan^- 1(1/3)+tan^- 1(2/9)+....+tan^- 1((2^(n-1))/(1+2^(2n-1)))+...... oo

Find the sum of the series : tan^- 1(1/3)+tan^- 1(2/9)+....+tan^- 1((2^(n-1))/(1+2^(2n-1)))+...... oo

tan^(-1)((n)/(n+1))-tan^(-1)(2n+1)=(3 pi)/(4)

The value of tan^-1(1/3)+tan^-1(2/9)+tan^-1(4/33)+tan^-1(8/129)+....n terms is: