If `x,y,z in N`. Then the probability that `x^2+y^2+z^2` is divisible by 7 is

If x,y,z in N. Then the probability that x^(2)+y^(2)+z^(z) is divisible by 7 is

If x+y+z=12 and x^(2)+y^(2)+z^(2)=96 and (1)/(x)+(1)/(y)+(1)/(z)=36 then the value x^(3)+y^(3)+z^(3) divisible by prime number is

Multiply: x^2+y^2+z^2-x y+x z+y z\ by x+y-z

If x prop y and y prop z , then prove that (x^7+y^7 +z^7) prop (x^5y^2 +x^3z^4 +y^5z^2)

Multiply: x^2+4y^2+z^2+2x y+x z-2y z\ by x-2y-z

Multiply: x^2+4y^2+z^2+2x y+x z-2y z\ by x-2y-z

x(y^(2)-z^(2))+y(z^(2)-x^(2))+z(x^(2)-y^(2)) is divisible by

If x,y and z satisfy given system of given equations: x^(2)+y^(2)+z^(2)=133,y+z-x=7,yz=x^(2) then the value of x+y+z is