" (ii) "quad (tan(A)/(2))/((a-b)(a-c))+(tan(a)/(2))/((b-a)(b-c))+(tan(C)/(2))/((c-a)(c-b))=(1)/(Delta)

The value of (tan((A)/(2)))/((a-b)(a-c))+(tan((B)/(2)))/((b-c)(b-a))+(tan((c)/(2)))/((c-a)(c-b))

In a triangle Delta ABC , prove the following : (tan A//2)/((a-b)(a-c))+(tan B//2)/((b-c)(b-a))+(tan C//2)/((c-a)(c-b)) = (1)/(Delta)

In a triangle Delta ABC , prove the following : (tan A//2)/((a-b)(a-c))+(tan B//2)/((b-c)(b-a))+(tan C//2)/((c-a)(c-b)) = (1)/(Delta)

In any Delta ABC(i)tan((B-C)/(2))=((b-c)/(b+c))(cot A)/(2)(ii)tan((A-B)/(2))=((a-b)/(a+b))(cot C)/(2)(iii)tan((C-A)/(2))=((c-a)/(c+a))(cot B)/(2)

If A+B+C=pi , then tan((A)/(2))tan((B)/(2))+tan((B)/(2))tan((C)/(2))+tan((C)/(2))tan((A)/(2)) is equal to a) (pi)/(6) b)3 c)2 d)1

1-tan(A)/(2)tan(B)/(2)=(2c)/(a+b+c)

(viii) (b+c-a) tan( A/2) = (c+a-b) tan( B/2) = (a+b-c) tan C/2

In triangle ABC, prove that, tan((B-C)/(2))=(b-c)/(b+c)cot((A)/(2)) tan((C-A)/(2))=(c-a)/(c+a)cot((B)/(2)) tan((A-B)/(2))=(a-b)/(a+b)cot((C)/(2))

In Delta ABC if tan((A)/(2))tan((B)/(2))+tan((B)/(2))tan((C)/(2))=(2)/(3) then a+c

(b-c)/(a) = (tan B/2-tan( c/2))/(tan B/2+tan C/2)