500 mL of 0.250 M `Na_(2)SO_(4)` solution is treated with 15.00 g of `BaCl_(2)`. Moles of `BaSO_(4)` formed are

500mL of 0.25M Na_(2)SO_(4) solution is added to an aquesous solution is 15g of BaCl_(2) resulting in the formation of a white precipatate of insoluble BaSO_(4) . How many moles and how many grams of BaSO_(4) are formed.

If law of conservation of mass holds good, 2.00 g of Na_(2)SO_(4) will react with 3.00 g of BaCl_(2) to produce BaSO_(4) equal to

What volume of 3M Na_(2)SO_(4) must be added to 25mL of 1M BaCl_(2) to produce 5g BaSO_(4) ?

30 mL of 0.2 N BaCl_(2) is mixed with 40 mL of 0.3 N Al_(2)(SO_4)_(3) . How many g of BaSO_(4) are formed?

30 mL of 0.2 N BaCl_(2) is mixed with 40 mL of 0.3 N Al_(2)(SO_4)_(3) . How many g of BaSO_(4) are formed?

If 200ml of 0.2 M BaCl_(2) solution is mixed with 500ml of 0.1M Na_(2)SO_(4) solution. Calculate osmotic pressure of resulting solutions , if temperature is 300 K ?

If 200ml of 0.2 M BaCl_(2) solution is mixed with 500ml of 0.1M Na_(2)SO_(4) solution. Calculate osmotic pressure of resulting solutions?

8 g of sulphur are burnt to form SO_(2) , which is oxidised by Cl_(2) water. The solution is treated with BaCl_(2) solution. The amount of BaSO_(4) precipitated is: