Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be `-4,-2 0,+2,-1` etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as
`"Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C)`
Where, `n_(H), n_(O) and n_(C)` are number of respective atoms
Oxidation state of carbon in diamond is:

Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be -4,-2 0,+2,-1 etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as "Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C) Where, n_(H), n_(O) and n_(C) are number of respective atoms Which of the following oxides of carbon has fractional oxidation state?

Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be -4,-2 0,+2,-1 etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as "Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C) Where, n_(H), n_(O) and n_(C) are number of respective atoms Which of the following compounds have zero oxidation state at carbon

Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be -4,-2 0,+2,-1 etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as "Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C) Where, n_(H), n_(O) and n_(C) are number of respective atoms In which of the following compounds, the valency of carbon is two?

The oxidation number of carbon in CH_2O is.

The oxidation number of carbon in CH_2O is.

The oxidation number of carbon in CH_(4) is

The valancy of carbons is generally 4 , but its oxidation state may be -4, -2, 0, +2, -1 , etc. In the compounds containing C, H , and O , the oxidation number of C is calculated as Oxidation number of C= (2n_(O)-n_(H))/(n_(C )) Where n_(O), n_(H) and n_(C ) are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. Teh oxidation of C in diamonds is

The valancy of carbons is generally 4 , but its oxidation state may be -4, -2, 0, +2, -1 , etc. In the compounds containing C, H , and O , the oxidation number of C is calculated as Oxidation number of C= (2n_(O)-n_(H))/(n_(C )) Where n_(O), n_(H) and n_(C ) are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. Teh oxidation of C in diamonds is