" reviden conce "[n+(n)/(2)+(n)/(4)+dots+9]" is "

Prove that (n!)/(r!)=n(n-1)(n-2)dots(r+1)

Prove that [(n+1)//2]^n >(n !)dot

Prove that [(n+1)//2]^n >(n !)dot

For all values of n. n ( n^(2) - 1) ( n^(2) - 4) ( n^(2) - 9)(n^(2) -16) (n^(2) -25) is divisible by

If f(x)=|x^nn !2cosxcos(npi)/2 4sinxsin(npi)/2 8| then find the value of (d^n)/(dx^n)([f(x)])_(x=0)dot(n in z)dot

If f(x)=|x^nn !2cosxcos(npi)/2 4sinxsin(npi)/2 8| then find the value of (d^n)/(dx^n)([f(x)])_(x=0)dot(n in z)dot

If (n)/(n+15) = 4/9 , then n = ?

(n!) / ((nr)!) = n (n-1) (n-2) dots (n- (r-1))

Find the sum of n terms \ of the series: 1/(1. 2)+1/(2. 3)+1/(3. 4)+dot+ 1/n dot((n+1))