" The Cartesian equation of a line "AB" is "(2x-1)/(sqrt(3))=(y+2)/(2)=(z-3)/(3)" .Find the direction cosines of a line "

The Cartesian equations of a line AB are (2x-1)/(sqrt(3))=(y+2)/2=(z-3)/3dot Find the direction cosines of a line parallel to AB.

The Cartesian equations of a line AB are (2x-1)/(sqrt(3))=(y+2)/2=(z-3)/3dot Find the direction cosines of a line parallel to AB.

If the cartesian equation of a line AB is (x-1)/(2)=(2y-1)/(12)=(z+5)/(3) , then the direction cosines of a line parallel to AB are -

The cartesian equation of a line AB is (3-x)/(1)=(y+2)/(-2)=(z-5)/(4) . Find the direction ratios of a line parallel to AB.

The cartesian equation of a line is (2x-5)/(3)=(6-3y)/(2)=(z+1)/(6) . Find the direction ratios of the given line.

The Cartesian equation of a line is (x-3)/(2)=(y+1)/(-2)=(z-3)/(5). Find the vector equation of the line.

The cartesian equation of a line AB is (3-x)/1=(y+2)/-2=(z-5)/4 . Find the direction ratios of a line parallel to AB.

The cartesian equation of a line is (x-3)/(2)=(y+1)/(-2)=(z-3)/(5). Find the vector equation of the line.

The cartesian equation of a line is (x-3)/(2)=(y+1)/(-2)=(z-3)/(5). Find the vector equation of the line.