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From the following molar conductivities...

From the following molar conductivities at infinite dilution `:`
`wedge_(m)^(@)` for `Ba(OH)_(2)=457.6Omega^(1)cm^(2)mol^(-1)`
`wedge_(m)^(@)` for `BaCl_(2)=240.6Omega^(-1) cm^(2)mol^(-1)`
`wedge_(m)^(@)` for `NH_(4)Cl=129.8 Omega^(-1) cm^(2) mol^(-1)`
Calculate `wedge_(m)^(@)` for `NH_(4)OH`.

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