Internal energy of `n_(1)` mol of hydrogen of temperature `T` is equal to the internal energy of `n_(2)` mol of helium at temperature `2T`. The ratio `n_(1) // n_(2)` is

Internal energy of n_1 moles of hydrogen at temperature T is equal to the internal energy of n_2 moles of helium at temperature 2T. Then the ratio n_1//n_2 is :

Internal energy of n_1 moles of hydrogen at temperature 150 K is equal to the in ternal energy of n_2 moles of helium at temperature 300 K The ratio of n_1//n_2 is

Internal energy of n_1 moles of hydrogen at temperature 150 K is equal to the in ternal energy of n_2 moles of helium at temperature 300 K The ratio of n_1//n_2 is

Internal energy of n moles of helium at temperature T_1 K is equal to the internal energy of 2n moles of oxygen gas at temperature T_2 K then the value of T_1 /T_2 will be

Internal energy of n moles of helium at temperature T_1 K is equal to the internal energy of 2n moles of oxygen gas at temperature T_2 K then the value of T_1 /T_2 will be

Find total internal energy of 3 moles of hydrogen gas at temperature T .

Find total internal energy of 3 moles of hydrogen gas at temperature T .

Calculate the change in internal energy of 3 .0 mol of helium gas when its temperature is increased by 2. 0 K .