The length of the tangent to the circle `x^(2)+y^(2)-2x-y-7=0` from (-1, -3), is

The length of the tangent of the circle x^2+y^2-2x-y -7 = 0 from the point (-1,-3) is

The length of the tangent drawn to the circle x^(2)+y^(2)-2x+4y-11=0 from the point (1,3) is

The locus of the point from which the length of the tangent to the circle x^(2)+y^(2)-2x-4y+4=0 is 3 units is

The locus of the point from which the length of the tangent to the circle x^(2)+y^(2)-2x-4y+4=0 is 3 units is

The locus of the point from which the length of the tangent to the circle x^(2)+y^(2)-2x-4y+4=0 is 3 units is

Length of the tangent. Prove that the length t o f the tangent from the point P (x_(1), y(1)) to the circle x^(2) div y^(2) div 2gx div 2fy div c = 0 is given by t=sqrt(x_(1)^(2)+y_(1)^(2)+2gx_(1)+2fy_(1)+c) Hence, find the length of the tangent (i) to the circle x^(2) + y^(2) -2x-3y-1 = 0 from the origin, (2,5) (ii) to the circle x^(2)+y^(2)-6x+18y+4=-0 from the origin (iii) to the circle 3x^(2) + 3y^(2)- 7x - 6y = 12 from the point (6, -7) (iv) to the circle x^(2) + y^(2) - 4 y - 5 = 0 from the point (4, 5).

The length of the tangent from (0, 0) to the circle 2(x^(2)+y^(2))+x-y+5=0 , is