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Let f1: R->R, f2:[0,oo)->R, f3:R->Rand f...

Let `f_1: R->R, f_2:[0,oo)->R, f_3:R->Rand f_4:R->[0,oo)` be defined by

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Let f_1:R→R,f_2:[0,∞)→R, f_3:R→R and f_4:R→[0,∞) be defined by f_1(x)={ ∣x∣ if x<0 ; e^x if x≥0 ; f_2(x)=x^2 ; f_3(x)={ sin x if x<0 ; x if x≥0 ; f_4(x)={ f_2(f_1(x)) if x<0 f_2(f_1(x)) if x≥0 ​then f_4 is

Let f_(1):R to R, f_(2):[0,oo) to R, f_(3):R to R and f_(4):R to [0,oo) be a defined by f_(1)(x)={{:(,|x|,"if "x lt 0),(,e^(x),"if "x gt 0):}:f_(2)(x)=x^(2),f_(3)(x)={{:(,sin x,"if x"lt 0),(,x,"if "x ge 0):} and f_(4)(x)={{:(,f_(2)(f_(1)(x)),"if "x lt 0),(,f_(2)(f_(1)(f_(1)(x)))-1,"if "x ge 0):} then f_(2) of f_(1) is

Let f(1):R to R, f_(2):[0,oo) to R, f_(3):R to R and f_(4):R to [0,oo) be a defined by f_(1)(x)={{:(,|x|,"if "x lt 0),(,e^(x),"if "x gt 0):}:f_(2)(x)=x^(2),f_(3)(x)={{:(,sin x,"if x"lt 0),(,x,"if "x ge 0):} and f_(4)(x)={{:(,f_(2)(f_(1)(x)),"if "x lt 0),(,f_(2)(f_(1)(f_(1)(x)))-1,"if "x ge 0):} Then, f_(4) is

Let f(1):R to R, f_(2):[0,oo) to R, f_(3):R to R and f_(4):R to [0,oo) be a defined by f_(1)(x)={{:(,|x|,"if "x lt 0),(,e^(x),"if "x gt 0):}:f_(2)(x)=x^(2),f_(3)(x)={{:(,sin x,"if x"lt 0),(,x,"if "x ge 0):} and f_(4)(x)={{:(,f_(2)(f_(1)(x)),"if "x lt 0),(,f_(2)(f_(1)(f_(1)(x)))-1,"if "x ge 0):} Then, f_(4) is

Let f_(1):R to R, f_(2):[0,oo) to R, f_(3):R to R and f_(4):R to [0,oo) be a defined by f_(1)(x)={{:(,|x|,"if "x lt 0),(,e^(x),"if "x gt 0):}:f_(2)(x)=x^(2),f_(3)(x)={{:(,sin x,"if x"lt 0),(,x,"if "x ge 0):} and f_(4)(x)={{:(,f_(2)(f_(1)(x)),"if "x lt 0),(,f_(2)(f_(1)(f_(1)(x)))-1,"if "x ge 0):} then f_(2) is

Let f_(1):R rarr R,f_(2):[0,oo)rarr R,f_(3):R rarr R and f_(4):R rarr[0,oo) be defined by

Let f_(1) : R to R, f_(2) : [0, oo) to R, f_(3) : R to R be three function defined as f_(1)(x) = {(|x|, x < 0),(e^x , x ge 0):}, f_(2)(x)=x^2, f_(3)(x) = {(f_(2)(f_1(x)),x < 0),(f_(2)(f_1(x))-1, x ge 0):} then f_3(x) is:

Let f_(1) : R to R, f_(2) : [0, oo) to R, f_(3) : R to R be three function defined as f_(1)(x) = {(|x|, x < 0),(e^x , x ge 0):}, f_(2)(x)=x^2, f_(3)(x) = {(f_(2)(f_1(x)),x < 0),(f_(2)(f_1(x))-1, x ge 0):} then f_3(x) is:

Le f:[0,\ oo)->R\ a n d\ g: R->R be defined by f(x)=sqrt(x) and g(x)=xdot Find f+g,\ f-g,\ fg\ a n df/gdot

Le f:[0,\ oo)->R\ a n d\ g: R->R be defined by f(x)=sqrt(x) and g(x)=xdot Find f+g,\ f-g,\ fg\ a n df/gdot