x=1 is the radical axis of the two orthogonally intersecting circles. If `x^(2)+y^(2)=4` is one of the circles, then the other circle, is

Let x - 4 = 0 be the radical axis of two circles which are intersecting orthogonally . If x^2 + y^2 = 36 is one of those circles , then the other circle is

Radical Axis Of Two Circles

Angle of intersection of two circle and orthogonal intersection of circles

If a circle Passes through point (1,2) and orthogonally cuts the circle x^(2)+y^(2)=4, Then the locus of the center is:

Find the point of intersection of the circle x^(2)+y^(2)-3x-4y+2=0 with the x -axis.

The centres of the circles are (a,c) and (b,c) and their radical axis is the y-axis . The radical of one of the circle is r . The radius of the other circle is

(a,c) and (b,c) are the centres of two circles whose radical axis is the y-axis.If the radius of the first circle is r then the diameter of the other circle is