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([[1,3],[-1,-4]]+[[3,-2],[-1,1]])[[1,3,5...

([[1,3],[-1,-4]]+[[3,-2],[-1,1]])[[1,3,5],[2,4,6]]

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If A=[[2,3,-4],[1,0,6],[-2,1,5]],B=[[5,1,2],[6,-1,4],[5,3,-4]] , find 2A-3B .

If A=[[2,3,-4],[1,0,6],[-2,1,5]],B=[[5,1,2],[6,-1,4],[5,3,-4]] , find 2A-3B .

Show that [[5,-1],[6,7]] [[2,1],[3,4]] ne [[2,1],[3,4]] [[5,-1],[6,7]]

If A = [(2,2,1), (1,3,1), (1,2,2)] then A^-1+(A-5I) (AI)^2 = (i) 1/ 5 [[4,2, -1], [-1,3,1], [-1,2,4]] (ii) 1/5 [[4, -2, -1], [-1, 3, -1], [-1, -2,4]] (iii) 1/3 [[4,2, -1], [-1,3,1], [-1,2,4]] (iv) 1/3 [[4, -2, -1], [-1,3, -1], [-1, -2,4]]

Without expanding prove that: |[12, 2, 4, -5, 1],[-8, 1, -5, 2, -1],[6, 4, a ,-3, 2],[-10, 2, 1 ,3 ,4],[-2, 4, 6 ,8, -5]|=|[12, -4, -8, 10, -2],[4, 1, -5, 2, -1],[-3, 4, a, -3, 2],[5, 2, 1, 3, 4],[1, 4, 6, 8, -5]| .

Delta=abs([1xx5,2xx5,3xx5],[3,1,6],[4,2,1]) =5 abs([1,2,3],[3,1,6],[4,2,1])

Compute the indicated products : (1) [{:(3,-1,4),(2,3,1):}][{:(1,3,4),(2,1,0),(-3,2,3):}] (2) [{:(1,3),(2,1):}][{:(4),(-1):}] (3) [{:(1,4,2),(5,-2,3):}][{:(2,-4),(1,-3),(4,0):}] (4) [1" "2," "3][{:(2),(4),(6):}] (5) [{:(2),(4),(6):}][1" "2," "3]

If A({:(1,3,4),(3,-1,5),(-2,4,-3):})=({:(3,-1,5),(1,3,4),(+4,-8,6):}) , then A=

If A({:(1,3,4),(3,-1,5),(-2,4,-3):})=({:(3,-1,5),(1,3,4),(+4,-8,6):}) , then A=

If A({:(1,3,4),(3,-1,5),(-2,4,-3):})=({:(3,-1,5),(1,3,4),(+4,-8,6):}) , then A=