(1+7i)/((2-i)^(2))" is "

Change the following complex numbers into polar form (1+ 7i)/((2-i)^(2))

Convert the following in the polar form : ( i ) (1+7i)/((2-i)^(2)) (ii) (1+3i)/(1-2i)

Express the following complex number in the polar form: (i) (1+7i)/((2-i)^(2))( ii) (1+3i)/(1-2i)

Represent the complex numbers (1+7i)/((2-i)^(2)) in polar form

(a) Express (1+7i)/((2-i)^(2)) in the form a+ib. (b) Reduce (1)/(1-4i)-(2)/(1+i) in the form a+ib.

Put the complex number (1+7i)/((2-i)^(2)) in the form r(cos theta+is int h eta) where r is a positive real number and * pi

Convert the following in the polar form: (1+7i)/((2-i)^(2))

If Z = (1+7i)/((2-i)^(2)) then the polar form of z is

Write the following complex numbers in polar form ((1+7i))/((2-i)^(2))