Lines 5x + 12y - 10 = 0 and 5x - 12y - 4...

Lines `5x + 12y - 10 = 0` and `5x - 12y - 40 = 0` touch a circle C1 of diameter 6. If the centre of C1, lies in the first quadrant then the equation of the circle C2, which is concentric with C1, and cuts intercepts of length 8 on these lines is

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Lines 5x + 12y - 10 = 0 and 5x - 12y - 40 = 0 touch a circle C1 of diameter 6. If the center of C1, lies in the first quadrant then the equation of the circle C2, which is concentric with C1, and cuts intercept of length 8 on these lines

Lines 5x + 12y - 10 = 0 and 5x - 12y - 40 = 0 touch a circle C1 of diameter 6. If the center of C1, lies in the first quadrant, find the equation of the circle C2, which is concentric with C1, and cuts intercept of length 8 on these lines

Lines 5x + 12 y -10=0 and 5x - 12y - 40=0 touch a circle C_(1) of diameter 6.If the centre of C_(1) lies in the first quadrant, find the equation of the circle C_(2) which is concentric with C_(1) and cuts, intercepts of length 8 on these lines.

If lines 5x + 12y-10 = 0 and 5x- 12y - 40 =0 touch a circle C_1 of diameter 6, and if the centre of C_1 lies in the first quadrant, find the equation of a circle C_2 , which is concentric with C_1 and cuts intercept of length 8 on these lines.

Find the equation of the circle with center at (3,-1) and which cuts off an intercept of length 6 from the line 2x-5y+18=0

The equation of the circle which touches the lines x=0, y=0 and x=c(c gt 0) is

Lines `5x + 12y - 10 = 0` and `5x - 12y - 40 = 0` touch a circle C1 of diameter 6. If the centre of C1, lies in the first quadrant then the equation of the circle C2, which is concentric with C1, and cuts intercepts of length 8 on these lines is

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