sin^(2)(pi)/(6)+cos^(2)(pi)/(3)-tan^(2)(pi)/(4)=(-1)/(2)

sin^(2)(pi)/(6)+cos^(2)(pi)/(3)-tan^(2)-(1)/(2)(pi)/(4)=-(1)/(2)

Find the value of the sin^(2)((pi)/(6))+cos^(2)((pi)/(3))-tan^(2)((pi)/(4))

Show / Prove/ Verify the following : (sin^(2)""(pi)/(6)+cos^(2)""(pi)/(3)+tan^(2)""(pi)/(6))/(sec^(2)""(pi)/(4)-cos^(2)pi)=(1)/(3).cos""(pi)/(3)+(1)/(sqrt3)sec""(pi)/(6)

sin^(2)""(2pi)/(3)+ cos^(2)""(5pi)/6-tan^(2)""(3pi)/4=

(sec^(2)(pi)/(4)-cot^(2)(pi)/(4))/(sin^(2)(pi)/(3)+cos^(2)(pi)/(6))+(sin^(2)(pi)/(2)-cos^(2)(pi)/(3))/((1)/(4)tan^(2)(pi)/(6))=9(2)/(3)

Evaluate (ii) sin^(2). (2pi)/(3) + cos^(2). (5pi)/(6) - tan^(2). (3 pi)/(4)

Prove that: sin^2frac (pi)(6)+cos^2frac (pi)(3)-tan^2frac (pi)(4)=-1/2

Prove that sin^2(pi/4) + cos^2(pi/6) - tan^2(pi/4) = 1/4

The value of 2sin^(2)((pi)/(3))-cos^(2)((pi)/(6))+tan^(2)(pi/6) is equal to ....