[" 144."475tan theta=44," the "],[(5sin theta-3cos theta)/(5sin theta+2cos theta)]

If 5tan theta=4 then value of ((5sin theta-3cos theta)/(5sin theta+3cos theta))=

If theta lies in the first quadrant and 5 tan theta = 4 , " then " (5 sin theta - 3 cos theta )/( sin theta + 2 cos theta )=

If theta lies in the first quadrant and 5 tan theta = 4 , " then " (5 sin theta - 3 cos theta )/( sin theta + 2 cos theta )=

If 5 tan theta =4 , then frac(5sin theta - 3cos theta )(5 sin theta + 2cos theta ) is equal to

If tan theta=5/6 then (12 sin theta-5cos theta)/(12sin theta+5cos theta)=

If 5tan theta=4, then (5sin theta-3cos theta)/(5sin theta+2cos theta) is equal to 0 (b) 1 (c) (1)/(6)(d)6

If theta in the first quadrant and 5 tan theta =4 " then " ( 5 sin theta - 3 sin theta)/( sin theta + 2 cos theta) is equal to